-4x^2+12x+7=16

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Solution for -4x^2+12x+7=16 equation: 



-4x^2+12x+7=16

We move all terms to the left:

-4x^2+12x+7-(16)=0

We add all the numbers together, and all the variables

-4x^2+12x-9=0

a = -4; b = 12; c = -9;
Δ = b2-4ac
Δ = 122-4·(-4)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-8}=1+1/2$

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